(9/2+x/3)^1/2=x+1

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Solution for (9/2+x/3)^1/2=x+1 equation:


x in (-oo:+oo)

((x/3+9/2)^1)/2 = x+1 // - x+1

((x/3+9/2)^1)/2-x-1 = 0

(x/3+9/2)/2-x-1 = 0

(1/3*x+9/2)/2-x-1 = 0

(1/3*x+9/2)/2+(2*(-x))/2+(-1*2)/2 = 0

1/3*x+2*(-x)-1*2+9/2 = 0

9/2-5/3*x-2 = 0

5/2-5/3*x = 0

(5/2-5/3*x)/2 = 0

(5/2-5/3*x)/2 = 0 // * 2

5/2-5/3*x = 0

5/2-5/3*x = 0 // - 5/2

-5/3*x = -5/2 // : -5/3

x = -5/2/(-5/3)

x = 3/2

x = 3/2

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